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MrRa [10]
2 years ago
12

0 y-

Mathematics
1 answer:
otez555 [7]2 years ago
4 0

Answer:

can you write these in proper way

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Order 34 × 102, 1.2 × 107, 8.11 × 10–3 and 435 from least to greatest.
andrey2020 [161]
I will assume that this question is about scientific notation (also assuming that the first number is 3.4*10^2), where you can arrange the numbers by the exponent of the 10, so from least to greatest:
8.11*10^{-3}, 3.4*10^{2}, 435, and 1.2*10^{7}
6 0
3 years ago
-1(-2x + 4) = 6<br><br> Hellooooooooooo
butalik [34]

Answer:

x=5

Step-by-step explanation:

First we distribute

2x-4=6

isolate x

2x=10

divide both sides by 2

x=5

(plz give brianliest ty)

6 0
3 years ago
Read 2 more answers
Make x the subject of the following: b = x - 5
nevsk [136]
B=x-5
To get x on its own you have to add 5 to both sides. This gives you:
b+5=x
or
x=b+5
8 0
3 years ago
3x-2=3<br> X=<br> Explain too please
Lubov Fominskaja [6]

3x-2=3

3x=3+2

3x=5

x=5/3

Answer : According to the information provided in the question, the value of 'x' is 5/3

5 0
3 years ago
Read 2 more answers
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
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