0 y-

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

8 0

3 years ago

Read 2 more answers

Tanya needs to buy chocolate bars for all the children in year 7. Each of the 130 children get one chocolate bar. There are 8 ch

Sedaia [141]

Answer:

17 packets

Step-by-step explanation:

So Tanya needs 130 chocolate bars.

But there is 8 in each packet.

So,

130 ÷ 8 = 16.25

16 packets

As you can see, there is a quarter left of chocolates that she needs (0.25). So what she can do is buy 1 more packet then give the quarter of that packet to the children.

So 16 + 1 = 17 packets

4 0

3 years ago

Read 2 more answers

I really need some help .............

Effectus [21]

Answer:

61

Step-by-step explanation:

add the number of minutes for each day and then divide that number by the number of days

$35+60+65+60+85$ $=305$

$305 / 5 = 61$

8 0

3 years ago

Read 2 more answers

The circle below has center P, and its radius is 3 m. Given that m 2 QPR=170°, find the length of the minor arc OR.

QveST [7]

Any smooth curve connecting two points is called an arc. The length of the arc m∠QPR is 2.8334π m.

<h3>What is the Length of an Arc?</h3>

Any smooth curve connecting two points is called an arc. The arc length is the measurement of how long an arc is. The length of an arc is given by the formula,

$\rm{ Length\ of\ an\ Arc = 2\times \pi \times(radius)\times\dfrac{\theta}{360} = 2\pi r \times \dfrac{\theta}{2\pi}$

where

θ is the angle, that which arc creates at the centre of the circle in degree.

Given the radius of the circle is 3m, while the angle made by the arc at the centre of the circle is 170°. Therefore,

The length of an arc = 2πr×(θ/360°) = 2π × 3 ×(170/360°) = 2.8334π m

Hence, the length of the arc m∠QPR is 2.8334π m.

Learn more about Length of an Arc:

brainly.com/question/1577784

#SPJ1

4 0

2 years ago

PLEASEEEE HELP HONESTLY REALLY NEED IT!!!!

Igoryamba

Answer:

Emma is right because Jon put ¨2.5¨ notebooks when there are really $5

Step-by-step explanation:

8 0

3 years ago