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astraxan [27]
3 years ago
9

Write an equation of the line in slope-intercept form given the

Mathematics
1 answer:
zlopas [31]3 years ago
3 0
Y=mx+b
m=slope=-5
b=yintercept=7

y=mx+b
y=-5x+7
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Please help apex ansers
goblinko [34]
The factorization of A is y = (x - 8)(x + 7).
The factorization of B is y = (x + 1)(x - 4)(x - 5)

In order to find these, you must first find where each graph crosses the x-axis. In the first problem it does so at 8 and -7. In order to find the correct parenthesis for those, you need to write it out as a statement and then solve for 0. 

x = 8 ---> subtract 8 from both sides
x - 8 = 0
This means we use (x -  8) in our factorization. 

You then need to repeat the process until you have all the pieces. In the second problem, there will be 3 instead of 2 since it crosses the axis 3 times. 
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What is the x intercept of the equation that passes through (1,-6) and is perpendicular to y=1/3x +1
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\bf y=\stackrel{slope}{\cfrac{1}{3}}x+1\impliedby \textit{slope of this line, so a perpendicular will be}&#10;\\\\\\&#10;\textit{perpendicular, negative-reciprocal slope for}\quad \cfrac{1}{3}\\\\&#10;negative\implies  -\cfrac{1}{ 3}\qquad reciprocal\implies - \cfrac{ 3}{1}\implies -3\\\\&#10;-------------------------------\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;&&(~1 &,& -6~)&#10;\end{array}

\bf slope =  m\implies -3&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-6)=-3(x-1)&#10;\\\\\\&#10;y+6=-3x+3\implies 0+6=-3x+3\implies 3=-3x\implies \cfrac{3}{-3}=x&#10;\\\\\\&#10;-1=x\qquad \qquad \qquad \qquad \qquad \qquad \qquad (~-1~,~0~)
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3 years ago
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