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Elena L [17]
3 years ago
9

What is 6 to 11 in the simplest form ?

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
6/11 is already in the simplest form. It can be written as 0.545455 in decimal form (rounded to 6 decimal places. )
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Hola me pueden ayudar?TwT​
Lana71 [14]

Answer:

Chinese noodles

Step-by-step explanation:

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3 years ago
Student lunch preference Pizza 18, Chicken Sandwich 9, Salad 6, hot dog 10, Steak sub 13
Vadim26 [7]

Answer:

112 i believe

Step-by-step explanation:

8 0
3 years ago
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HELP I NEED THIS DONE QUICKK CAN ANNYONE HELP???????????????????????????????????????????????????????????????????????????????????
natulia [17]
For the first question, it would be D: \frac{1}{3} ÷ 9. This is because to solve a division problem with fractions, you would need to multiply the first fraction by the reciprocal of the second fraction. For the second question, the answer would be D: 32. This can be solved by dividing 8 by \frac{1}{4} or 0.25. For the third question, it would be D. \frac{1}{12}. This can be solved by dividing \frac{1}{4} by 3. For the fourth question, the answer would be \frac{1}{12}. This can be found by flipping the 4, which would make it look like \frac{1}{4}, and multiplying it by \frac{1}{3}. For the last question, 1 would be B, 2 would be C, 3 would be C, and 4 would be A.

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6 0
3 years ago
A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
Ludmilka [50]

Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
3 years ago
A factory produces 42,000 computer monitors per day. The manager of the factory claims that fewer than 660 defective computer mo
Oksana_A [137]

Answer:

<h2> The manager's claim is likely to be true.</h2>

Step-by-step explanation:

We are given that the factory produces  42,000  computer monitors per day

And the claim is of this amount produces fewer than 660 are defective.

a random sample shows that of 240 monitors 2 are defective

to verify the factory managers claim we need to know how many 240s are there in 42000

=42000/240= 175

Since each 240 will give 2 defective monitors

175 will give= 175*2= 350

350 is less than 660 hence the managers claim is correct

5 0
3 years ago
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