Answer:
Length = 16 inches and width = 12inches
Step-by-step explanation:
A = 192 in² . The width is 4 + 1/2x. therefore let x = length
Area = LW
192 = x(4 + 1/2 x)
192 = 4x + 1/2x²
384 = 8x + x² Multiply each term by 2 to make a
384 + 16 = x² + 8x + 16 Complete the square
400 = (x + 4)²
± 20 = x + 4
20 = x + 4 or -20 = x + 4
20 - 4 = x or -20 - 4 = x
16 = x or -24 = x reject the negative amount
Length = 16
width = 4 + 1/2(16); 4 + 8 = 12
Answer:
The answer is stratified.
Step-by-step explanation:
I saw the image that should have been posted with this word problem.
The rolls of wrapping paper is cylindrical in shape.
Roll A : length = 30 inches ; diameter = 3 inches
Roll B : length = 24 inches ; diameter = unknown
Lateral surface area = 2 π r h
Lateral Surface area of Roll A = Lateral Surface area of Roll B
2 * 3.14 * 1.5in * 30in = 2 * 3.14 * r * 24 in
282.60 in² = 150.72 in * r
282.60 in² / 150.72 in = r
1.875 in = r
diameter is 2 times the radius = 1.875 in * 2 = 3.75 inches
The diameter of Roll B is 3.75 inches.
Neither of the equations are parallel or perpendicular
