3 years ago

Factor each monomial 30m2n

Mathematics

1 answer:

I am Lyosha [343]3 years ago

4 0

This is the answer (2•3•5m2n)

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A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus

xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± $z\frac{\sigma}{\sqrt n}$

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 27.4 - $2.58\times\frac{5.75}{\sqrt{7}}$

Lower limit of Confidence interval = 21.79

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Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

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3 years ago