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4 years ago

What is the value of x in the equation 4x + 8y = 40, when y = 0.8?

2 answers:

8 0

4x + 8y = 40

When y = 0.8
4x + 8(0.8) = 40
4x + 6.4 = 40
4x = 40 - 6.4
4x = 33.6
x = 8.4

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Answer: x = 8.4
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storchak [24]4 years ago

3 0

To find your answer you must substitute y for 0.8
4x + (8)(0.8) = 40
Now solve for x
====================================================================
SOLVING...

4x + (8)(0.8) = 40
4x + 6.4 = 40

Subtract 6.4 from each side
4x+ 6.4 − 6.4 = 40 − 6.4
4x = 33.6

Divide each side by 4
4x ÷ 4 = 33.6 ÷ 4
x = 8.4

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If A= [2 6] prove that (A')' = A 3 7 4 9

Ivanshal [37]

Answer:if A= [2 6] prove that (A')' = A

3 7

4 9

Step-by-step explanation:

3 0

1 year ago

See the picture below

mart [117]

Answer:

a) 301.59 cubic centimeters

b) 235.87 square centimeters

Step-by-step explanation:

Volume of ice cream cone is volume of hemisphere PLUS volume of cone.

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}$

radius is given as 4, so,

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}\\=\frac{\frac{4}{3}\pi (4)^3}{2}\\=134.04$

Now, Volume of Cone = $\frac{1}{3}\pi r^2 h$

Where radius is 4 and height is 10, so,

Volume of Cone = $\frac{1}{3}\pi r^2 h\\=\frac{1}{3}\pi (4)^2 (10)\\=167.55$

Volume of Ice Cream Cone = 134.04 + 167.55 = 301.59 cubic centimeters

Surface area of ice cream cone is surface area of hemisphere PLUS surface area of cone.

Surface Area of Hemisphere = $2\pi r^2\\=2\pi (4)^2\\=100.53$

Surface Area of Cone = $\pi r^2+\pi rl$

We dont need to use the first part, $\pi r^2$ since it is "inside". We need to find l, slant height, by using pythagorean theorem on a triangle we can make (bottom right).

4^2 + 10^ 2 = l^2

16 + 100 = l^2

116 = l^2

l = 10.77

Now to find the surface area of cone = $\pi rl\\=\pi (4)(10.77)\\=135.34$

Surface area of ice cream cone = 100.53 + 135.34 = 235.87 square centimeters

5 0

3 years ago

Explain, with a test, why the two triangles in each figure are similar. Find the

frutty [35]

Answer:

x = 3, y = 6

Step-by-step explanation:

In the figure attached,

If ΔADE and ΔABC are similar triangles, their corresponding sides will be in the same ratio.

By this property,

$\frac{AB}{AD}=\frac{AC}{AE}=\frac{BC}{DE}$

$\frac{AB}{AD}=\frac{AC}{AE}$

$\frac{AD+BD}{AD}=\frac{AE+EC}{AE}$

$\frac{3}{2}=\frac{x+1.5}{x}$

3x = 2x + 3

3x - 2x = 3

x = 3

Similarly, $\frac{AB}{AD}=\frac{BC}{DE}$

$\frac{3}{2}=\frac{y}{4}$

y = $\frac{3\times 4}{2}$

y = 6

7 0

3 years ago

Please help. 50 points + brainliest

Korvikt [17]

Answer:

1. (a-c) $\sqrt{x}$ + b $\sqrt{y}$

2. 9m + 2 $\sqrt{n}$

3. 6a

4. (5a - 3b) $\sqrt{5y}$

Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5 $\sqrt{n}$ and -3 $\sqrt{n}$ combined equals 2 $\sqrt{n}$

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

5a $\sqrt{5y}$ - 3b $\sqrt{5y}$

We can combine the two like terms and get the final answer above.

please give thanks by clicking the heart :)

3 0

3 years ago

Can you please explain how to write the ratios for sin x and cos x? When angles are x, y, and z. The hypotenuse being 12 and is

Kamila [148]

Your triangle has acute angles X and Y, and right angle Z.

For an acute angle A in a right triangle:

The sine is the ratio of the opposite leg to the hypotenuse.
sin A = opp/hyp

The cosine is the ratio of the adjacent leg to the hypotenuse.
cos A = adj/opp

The hypotenuse of a right triangle is the side opposite the right angle. It is the longest side of a right triangle. There is only one hypotenuse in a triangle, so there is no confusion with the hypotenuse.

The two sides that form the right angle are called the legs. Each leg is opposite an acute angle. The legs may or may not be congruent to each other, but each leg is always shorter than the hypotenuse. Since there are two legs, we need to be able to distinguish them. If you take an acute angle as your angle of interest, the leg that is part of the angle is called the adjacent leg. The other leg is the opposite leg. Adjacent leg and opposite leg are relative terms. They depend on the acute angle you are considering.

For your triangle, if you look at angle X, then the adjacent leg is side XZ. The opposite leg for angle X is side YZ.

Using the ratios mentioned above for sine and cosine, you get:

sin X = opp/hyp = sqrt(119)/12

cos X = adj/hyp = 5/12

7 0

3 years ago