Hello,
A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2
Slope of the perpendicular: 1
y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.
Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q
|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....
X=7y-8 because subtract 7y from both sides and then multiply by 1
Answer:
C
Step-by-step explanation:
Since this is an indererminate form, use L'Hopital
d(sint)/dt = cos(t)
d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]
As t --> 0,
cos(0) = 1
(2e^t)/[2e^t - 1] = 2
1/2 is the limit
Answer:
DE≈16.1
m<E≈60.3
m<D≈29.7
Step-by-step explanation: