Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
Answer:
y=-3x+4
Step-by-step explanation:
Using the formula y=mx+b
mx= slope b= y-intercept
hence,
y=-3x+4 has a y-intercept of (0,4)
Given that,
Shelley's pet food store sold one customer 5 peanut butter biscuits for $3. She sold another customer 7 beef treats for $4.20.
For peanut, the cost is ratio is
For beef, the ratio is
If we take cross product of these items,
It implies, that the sale is in true proportion. From the cross product, we find that it is equal.
Answer:
stand up guy wont speak on nothign i speak or saw
Step-by-step explanation:
so, no breaks on the denominator thus, the LCD will be all three then.
![\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)} \\\\\\ \cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)} \\\\\\ \cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)} \\\\\\ \cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B3%7D%7Bx-2%7D%2B%5Ccfrac%7B4%7D%7Bx-1%7D-%5Ccfrac%7B1%7D%7Bx%7D%5Cimplies%20%5Ccfrac%7B%5B3x%28x-1%29%5D%2B%5B4x%28x-2%29%5D-%5B%28x-2%29%28x-1%29%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B%5B3x%5E2-3x%5D%2B%5B4x%5E2-8x%5D-%5Bx%5E2-3x%2B2%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B3x%5E2-3x%2B4x%5E2-8x-x%5E2%2B3x-2%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B6x%5E2-8x-2%7D%7Bx%28x-2%29%28x-1%29%7D%5Cimplies%20%5Ccfrac%7B2%28x%5E2-4x-1%29%7D%7Bx%28x-2%29%28x-1%29%7D)
