Given:
The right triangular prism.
Height of prism = 28 in.
Hypotenuse of base = 25 in.
leg of base = 24 in.
To find:
The lateral surface area of the prism.
Solution:
Pythagoras theorem:

Using Pythagoras theorem in the base triangle, we get




The perimeter of the triangular base is:


Lateral area of a triangular prism is:

Where, P is the perimeter of the triangular base and h is the height of the prism.
Putting
in the above formula, we get


Therefore, the lateral area of the prism is 1568 in².
Answer:
y-7=1/4(x+5)
Step-by-step explanation:
y-3=-4(x+2)
y=-4x-8+3
y=-4x-5
-----------
y-y1=m(x-x1)
y-7=m(x-(-5))
y-7=m(x+5)
perpendicular means negative reciprocal of the slope,
so the slope will be 1/4
y-7=1/4(x+5)
Answer:
4+4+4
Step-by-step explanation:
4^3 means 4 cubed which is equal to 4 added three time
1. <APC = <DQB [ Given]
2. Arc(AC = BD) [ Equal angles subtend equal arcs]
3. AB//CD [From 2]
Answer: -3+2 = -1 / -5+-1 = -6 / 6+-4 = 2 / -2+-7 = -9
Step-by-step explanation: oof