3 4/5 because if 5 only goes into 19 3 times and then there is 4/5 left
Answer:
$46
Step-by-step explanation:
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
f ( - 2 ) = - 12
Step-by-step explanation:
f ( - 2 ) = - 3 ( -2 )^2
then you do the exponent first so
- 3 ( 4 )
now you multpily the - 3 and 4
you get - 12
What are we supposed to be doing