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attashe74 [19]
3 years ago
14

Solve the system. Estimate the solution first. Enter whole numbers for the estimated solution and improper fractions in simplest

form for the algebraic solution.
braceleftze 6x + y = 2
x − 4y = 2
The estimated solution is (, ).
The algebraic solution is
Mathematics
1 answer:
Papessa [141]3 years ago
6 0

The estimated solution is (0,0 ).

The algebraic solution is (\frac{2}{5},\frac{-2}{5})\\

Step-by-step explanation:

We need to solve the system of equations:

6x + y = 2\\x -4y = 2

Solving using Elimination method

Let: 6x + y = 2\,\,eq(1)\\x -4y = 2\,\,eq(2)

Multiply eq(1) by 4 and add eq(1) and eq(2)

24x+4y=8\\x -4y = 2\\------\\25x=10\\x=\frac{10}{25}\\x=\frac{2}{5}\\

So, value of x is x=\frac{2}{5}\\ Converting into whole number: x=0

Now finding value of y

Putting value of x into eq(1)

6x+y=2\\6(\frac{2}{5})+y=2\\\frac{12}{5}+y=2\\y=2-\frac{12}{5}\\y=\frac{10-12}{5}\\y=\frac{-2}{5}\\

So, value of y is y=\frac{-2}{5}\\ Converting into whole number: y=0

The estimated solution is (0,0 ).

The algebraic solution is (\frac{2}{5},\frac{-2}{5})\\

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

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Step 1

Find the Volume of the two balls

we know that

the Volume of a sphere is equal to

V=\frac{4}{3} \pi r^{3}

In this problem we have

r=1.5\ in

Substitute

V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}

so

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V=2*4.5\pi=9 \pi\ in^{3}

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to    

V=\pi r^{2}h

In this problem we have

r=1.5\ in

h=4*r=4*1.5=6\ in    

Substitute

V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}    

Step 4

Find the volume of the square prism

The volume of the prism is equal to

V=Bh

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

B=(2*1.5)^{2}=9\ in^{2} -----> the base is equal to the diameter    

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Substitute

V=9*6=54\ in^{3}

Step 5

Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

54\ in^{3}-9\pi\ in^{3}=25.73\ in^{3}  

Step 6

Compare the amount of wasted space

the amount of wasted space in the cylinder is 14.14\ in^{3}

the amount of wasted space in the prism is  25.73\ in^{3}

Find the difference

25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}

The package that has the least amount of wasted space is the cylinder

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