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2 years ago

the sum of two numbers is 123. when the larger number is added to 5 times the smaller, the sum is 343. find the numbers.

2 answers:

3 0

Create a system of equations
x + y = 123
5x + y = 343

I use substitution
y = 123 - x
5x + 123 - x = 343
4x + 123 = 343
4x = 220
x = 55

Plug in
x + y = 123
55 + y = 123
y = 68

Check
5x + y = 343
5(55) + 68 = 343
275 + 68 = 343
343 = 343

nordsb [41]2 years ago

3 0

234+657=985 62793)2799994)252888

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Answer:

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Step-by-step explanation:

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x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)

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3 years ago

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2 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

2 years ago

HELP, I’M STUCK !

vaieri [72.5K]

Since P(X = x) = 0.3 for all 0 ≤ x ≤ α, we have

$\displaystyle\int_{-\infty}^\infty P(X=x)\,\mathrm dx=1\implies0.3\int_0^\alpha\mathrm dx=0.3\alpha=1\implies\alpha=\dfrac{10}3$

So,

$P(X>2) = \displaystyle\int_2^\infty P(X=x)\,\mathrm dx=0.3\int_2^{\frac{10}3}\mathrm dx$

$P(X>2)=0.3\left(\dfrac{10}3-2\right)=\boxed{\dfrac25}$

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2 years ago

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djyliett [7]

Answer:

6) D

8) E

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2 years ago

the sum of two numbers is 123. when the larger number is added to 5 times the smaller, the sum is 343. find the numbers.​

the sum of two numbers is 123. when the larger number is added to 5 times the smaller, the sum is 343. find the numbers.