Question

What is the area of this figure?

Answer 1

Answer:

          $\large\boxed{\large\boxed{42 unit^2}}$

Explanation:

The figure is not a regular hexagon. It is an irregular hexagon.

Please, find attached the picture with the original question and the figure.

You can split the figure into two triangles and one rectangle.

The rectangle has dimensions: 7units × 4units, thus its area is 28 units².

Both the upper triangle and lower triangle have base 7 units and height 2 units.

Hence the area of each triangle is:

       $area=(1/2)base\times height$

       

      $area=(1/2)7units\times 2units = 7units^2$      

Hence, the area of the hexagon is:

           $28units^2+7units^2+7units^2=42units^2$