In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
He is 38 kg.
I'll use only the first letters of their names, to make it simpler:
S+L=54.75
S+M=105
M=4L
S+4L=105
105-54.75=4L-L=3L
L=50.25/3=16.75
S=54.75-16.75=38
Answer:
{7x^2+168x+840}/{x+12}
Step-by-step explanation:
It's 82 degrees. Subtract your minor arc (98) by 360 to get your major arc, which is 262. Then, subtract 98 (minor arc) from 262 (major arc), which gives you 164. Finally, divide 164 by 2 to get angle ABC.
