Answer:
message it will be easy er to explain
Step-by-step explanation:
the solution is here,
the coordinate of centre of circle A is (3,2)
and the coordinate of centre of circle B is (3,0).
so the translation point from A to B is (3-0,0-2)=(3,-2).
Now the translation rule is given by (x+h,y+k)
where h is the tranalation anlong the x-axis and k is the translation along the y-axis.
For this problem, translation ruleis (x+3,y-2).
Then, radius of circle A(r1)=2 units
radius of circle B (r2)= 3 units
as the circle A is translated to B, the scale factor is
r2/r1=3/2=1.5
In conclusion, the translation rule for given circles is (x+3,y-2) and its scale factor is 1.5
8.213, 8.214 just add 1 hundred to the end
Answer:
The value at x =3 is undefined for the given expression
Step-by-step explanation:
Given expression is 
To find for what value of x is undefined in the given expression :



If we put x=3 in the above expression we get



Therefore 
The value at x =3 is undefined for the given expression
I got S > 2
Because you would multiply both sides by two then subtract by twelve
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