No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
I’m pretty sure the answer would be B
Answer:
Happy paws
y = 20 + 4x
Woof watchers
y = 9 + 5x
x = 11 hours
Step-by-step explanation:
Let
Number of hours = x
Total cost = y
Total cost = fixed cost + variable cost
The equations are:
Happy paws
y = 20 + 4x
Woof watchers
y = 9 + 5x
solve the equation to find for how many hours the total cost of the services is equal.
Equate total cost of both services
20 + 4x = 9 + 5x
Collect like terms
20 - 9 = 5x - 4x
11 = x
x = 11 hours
Check:
Happy paws
y = 20 + 4x
= 20 + 4(11)
= 20 + 44
= 64
Woof watchers
y = 9 + 5x
= 9 + 5(11)
= 9 + 55
= 64
A=1 and 2
B=2 and 4
C=1,2,7 and 14
D=1,2,4,and 8
Answer:
980
Step-by-step explanation:
I did it
