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2 years ago

What is the lateral surface area of a cone with radius 19 cm and slant height 11 cm?

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

8 0

Answer:

About 1310.469 cm³

Step-by-step explanation:

The formula is $\pi r\sqrt{h^2+r^2}=\pi\cdot19\cdot\sqrt{11^2+19^2}\approx1310.46973$

Hope this helps, and PM me with any more questions!

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An ice-cream store sold 70 sundaes. The ratio of

elixir [45]

Answer:

30 strawberry sundaes.

Step-by-step explanation:

We know there is a total of 70 sundaes.

3 sundaes will be strawberry.

4 sundaes will be choclate.

When you add 3 and 4 together, you get 7. This is your total ratio.

So 3/7 of the sundaes are strawberry.

And 4/7 of sundaes are choclate.

We know there is a total of 70 sundaes.

The total ratio we figured out is 7.

If the total sundaes is 70, and the total ration is 7. Then the total sundaes is 10 times bigger than the ratio.

This means we need to multiply the 3 strawberry sundaes and 4 choclate sundaes by 10.

3*10=30

4*10=40

So there are 30 strawberry sundaes and 40 choclate sundaes.

We need to find the strawberry sundae amount, so the answer is 30.

Hope this helps!

3 0

2 years ago

Helppp!!! i need help

klio [65]

Answer:

rectangle

kite

Step-by-step explanation:

4 0

2 years ago

Translate the word phrase into a variable expression.

NemiM [27]

<span>The word decreased by means subtract.
So...
Lets look at A.
A: a-b
Sound correct?
No,
Because the sentence said that "a is decreased by the number b."
Lets look at B.
B. b-a
Sound correct?
Yes,
Because a is getting decreased by b.

Your answer is, B.

Hope this helps!(:
</span>

8 0

2 years ago

What is the derivative of x times squaareo rot of x+ 6?

Dafna1 [17]

Hey there, hope I can help!

$\mathrm{Apply\:the\:Product\:Rule}: \left(f\cdot g\right)^'=f^'\cdot g+f\cdot g^'$
$f=x,\:g=\sqrt{x+6} \ \textgreater \ \frac{d}{dx}\left(x\right)\sqrt{x+6}+\frac{d}{dx}\left(\sqrt{x+6}\right)x \ \textgreater \ \frac{d}{dx}\left(x\right) \ \textgreater \ 1$

$\frac{d}{dx}\left(\sqrt{x+6}\right) \ \textgreater \ \mathrm{Apply\:the\:chain\:rule}: \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx} \ \textgreater \ =\sqrt{u},\:\:u=x+6$
$\frac{d}{du}\left(\sqrt{u}\right)\frac{d}{dx}\left(x+6\right)$

$\frac{d}{du}\left(\sqrt{u}\right) \ \textgreater \ \mathrm{Apply\:radical\:rule}: \sqrt{a}=a^{\frac{1}{2}} \ \textgreater \ \frac{d}{du}\left(u^{\frac{1}{2}}\right)$
$\mathrm{Apply\:the\:Power\:Rule}: \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1} \ \textgreater \ \frac{1}{2}u^{\frac{1}{2}-1} \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{u}}$

$\frac{d}{dx}\left(x+6\right) \ \textgreater \ \mathrm{Apply\:the\:Sum/Difference\:Rule}: \left(f\pm g\right)^'=f^'\pm g^'$
$\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(6\right)$

$\frac{d}{dx}\left(x\right) \ \textgreater \ 1$
$\frac{d}{dx}\left(6\right) \ \textgreater \ 0$

$\frac{1}{2\sqrt{u}}\cdot \:1 \ \textgreater \ \mathrm{Substitute\:back}\:u=x+6 \ \textgreater \ \frac{1}{2\sqrt{x+6}}\cdot \:1 \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{x+6}}$

$1\cdot \sqrt{x+6}+\frac{1}{2\sqrt{x+6}}x \ \textgreater \ Simplify$

$1\cdot \sqrt{x+6} \ \textgreater \ \sqrt{x+6}$
$\frac{1}{2\sqrt{x+6}}x \ \textgreater \ \frac{x}{2\sqrt{x+6}}$
$\sqrt{x+6}+\frac{x}{2\sqrt{x+6}}$

$\mathrm{Convert\:element\:to\:fraction}: \sqrt{x+6}=\frac{\sqrt{x+6}}{1} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}}{1}$

Find the LCD
$2\sqrt{x+6} \ \textgreater \ \mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}\cdot \:2\sqrt{x+6}}{2\sqrt{x+6}}$

$Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions$
$\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{x+2\sqrt{x+6}\sqrt{x+6}}{2\sqrt{x+6}}$

$x+2\sqrt{x+6}\sqrt{x+6} \ \textgreater \ \mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}$
$\sqrt{x+6}\sqrt{x+6}=\:\left(x+6\right)^{\frac{1}{2}+\frac{1}{2}}=\:\left(x+6\right)^1=\:x+6 \ \textgreater \ x+2\left(x+6\right)$
$\frac{x+2\left(x+6\right)}{2\sqrt{x+6}}$

$x+2\left(x+6\right) \ \textgreater \ 2\left(x+6\right) \ \textgreater \ 2\cdot \:x+2\cdot \:6 \ \textgreater \ 2x+12 \ \textgreater \ x+2x+12$
$3x+12$

Therefore the derivative of the given equation is
$\frac{3x+12}{2\sqrt{x+6}}$

Hope this helps!

8 0

2 years ago

Describe what is being done in each step while solving the equation. Match each step with the correct description. HINT: Start w

Licemer1 [7]

1. Original equation
2.Distributive property
3. Add 6x to each side
4. Subtract 2 from each side
5. Divide each side by 11

5 0

2 years ago