Find the distance CD rounded to the nearest tenth (5-2)^2 +(6-2)^2
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Answer:
4(x-8)=-32+4: x=1
2(x-2)=-3-2x: x1/4
3+5x=5(x+2)-7: x=0
8x+38=-3(-6-4x) x=5
Step-by-step explanation:
4(x-8)=-32+4
add subtract the numbers
-32+4=-28
4(x-8)=-28
Divide both sides by 4
Simplify
x-8=-7
Add 8 on both sides
x+8-8=-7+8
Simplify
x=1
2(x-2)=-3-2x
- Expand 2(x-2)
- apply distributive law: a(b-c)=ab-ac
a=2 b=x c=2
=2x-2·2
- multiply the numbers
2·2=4
=2x-4
2x-4=-3x-2
- Add 4 to both sides
2x-4+4=-3-2x+4
- simplify
2x=-2x+1
- Add 2x on both sides
2x+2x=2x+1+2x
- Simplify
4x=1
- Divide by 4 on both sides
4x÷4=1÷4
- Simplify
x=1/4
3+5x=5(x+2)-7
<em> We move all terms to the left: </em>
<em> 3+5x-(5(x+2)-7)=0 </em>
<em> We calculate terms in parentheses: -(5(x+2)-7), so: </em>
<em> 5(x+2)-7 </em>
<em> We multiply parentheses </em>
<em>5x+10-7 </em>
<em> We add all the numbers together, and all the variables </em>
<em> 5x+3 </em>
<em> Back to the equation: </em>
<em> -(5x+3) </em>
<em> We get rid of parentheses </em>
<em> 5x-5x-3+3=0 </em>
<em> We add all the numbers together, and all the variables </em>
<em> =0 </em>
<em> x=0/1 </em>
<em> x=0</em>
8x+38=-3(-6-4x)
Simplifying
8x + 38 = -3(-6 + -4x)
Reorder the terms:
38 + 8x = -3(-6 + -4x)
38 + 8x = (-6 * -3 + -4x * -3)
38 + 8x = (18 + 12x)
Solving
38 + 8x = 18 + 12x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-12x' to each side of the equation.
38 + 8x + -12x = 18 + 12x + -12x
Combine like terms: 8x + -12x = -4x
38 + -4x = 18 + 12x + -12x
Combine like terms: 12x + -12x = 0
38 + -4x = 18 + 0
38 + -4x = 18
Add '-38' to each side of the equation.
38 + -38 + -4x = 18 + -38
Combine like terms: 38 + -38 = 0
0 + -4x = 18 + -38
-4x = 18 + -38
Combine like terms: 18 + -38 = -20
-4x = -20
Divide each side by '-4'.
x = 5
Simplifying
x = 5
Hope this helps