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3 years ago

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on a random Monday in the spring, 95% of students are present at school. if there are 589 students present, then how many studen

ts are enrolled?

1 answer:

Rus_ich [418]3 years ago

6 0

Answer:

620

Step-by-step explanation:

95% × 620 =

(95 ÷ 100) × 620 =

(95 × 620) ÷ 100 =

58,900 ÷ 100 =

589;

You might be interested in

Please provide an answer

Igoryamba

Answer:

Step-by-step explanation:

The opposite angles in a quadrilateral theorem states that when a quadrilateral is inscribed in a circle, the angles that are opposite each other are supplementary, their degree measures add up to 180 degrees. One can apply this here by using the sum of (<C) and (<A) to find the measure of the parameter (z). Then one can substitute in the value of (z) to find the measure of (<B). Finally, one can use the opposite angles in a quadrilateral theorem to find the measure of angle (<D) by using the sum of (<B) and (D).

Use the opposite angles in an inscribed quadrialteral theorem,

<A + <C = 180

Substitute,

14x - 7 + 8z = 180

Simplify,

22z - 7 = 180

Inverse operations,

22z = 187

z = $\frac{187}{22}$

Simplify,

z = $\frac{17}{2}$

Now substitute the value of (z) into the expression given for the measure of angle (<B)

<B = 10z

<B = 10( $\frac{17}{2}$ )

Simplify,

<B = 85

Use the opposite angles in an inscribed quadrilateral theorem to find the measure of (<D)

<B + <D = 180

Substitute,

85 + <D = 180

Inverse operations,

<D = 95

8 0

3 years ago

Read 2 more answers

An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.

SCORPION-xisa [38]

Answer:

(a)See below

(b)I) 0.125 (ii)0.828125 (iii)0.234375 (iv) 0.625 (v)0.65625

Step-by-step explanation:

When an 8-sided die is rolled twice, the sample space is the set of all possible pairs (a,b) where a is the 1st outcome and b is the 2nd outcome.

The sample space is:

$[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]$

<u>PART A</u>

The sample space of the product a*b of each pair forms the required possibility diagram.

This is given as:

$1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64$

<u>PART B</u>

I) A prime number

The number of products that gives prime numbers = 8

The probability that the product is a prime number

$=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125$

ii) Not a perfect square

Number of products that results in perfect squares =11

The probability that the product is not a perfect square

$=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125$

iii) A multiple of 5

Number of products that are multiples of 5=15

The probability that the product is a multiple of 5

$=\dfrac{15}{64}\\=0.234375$

iv) Less than or equal to 21

Number of products which are less than or equal to 21=40

The probability that the product less than or equal to 21

$=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625$

v) Divisible by 4 or 6

Number of products divisible by 4 or 6= 42

The probability that the product is divisible by 4 or 6

$=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625$

8 0

3 years ago

Aubrey's parents are signing her up for summer camps. If there are 5 weeklong camps to choose from, in how many orders can they

Tems11 [23]

Answer:

This can be done in a total of 10 ways

Step-by-step explanation:

This is a selection problem.

What we are trying to do is to properly select 3 week long camps from the total 5. we are looking for the number of ways in which we can do this.

Now, since this is a selection problem, the proper mathematical term and approach to use is the COMBINATION

Mathematically, having r items to pick from a total n, the number of ways to do this is nCr ways

which is mathematically equivalent to;

n!/(n-r)!r!

now applying this to the problem at hand, what we have is 5C3

= 5!/(5-3)!3! = 5!/2!3! = (5 *4)/2 = 20/2 = 10 ways

3 0

4 years ago

Find the slope and the y- intercept of the line: y= 3x - 1

AlekseyPX

The slope is the number and/ or fraction that is being multiplied by X. the Y- intercept is the +/ - of a number at the end of the equation.
ANSWER SLOPE》 3
ANSWER Y- INTERCEPT》 -1

5 0

3 years ago

Read 2 more answers

Resolve into factors:2p(p-1)-p+1

Vlad1618 [11]

Answer:

(2p-1)(p-1)

Step-by-step explanation:

=> 2p(p-1)-p+1

Opening brackets

=> 2p²-2p-p+1

=> 2p²-3p+1

Using mid-term break formula

=> 2p²-2p-p+1

=> 2p(p-1)-1(p-1)

=> (2p-1)(p-1)

5 0

3 years ago