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Varvara68 [4.7K]
4 years ago
14

If 7 notepads cost $3.15, what is the unit price of the notepads?

Mathematics
2 answers:
vovangra [49]4 years ago
6 0

Answer:

$0.45

Step-by-step explanation:

Unit price is basically the same as unit rate. Unit rate is the cost of one item.

So $3.15 divided by seven is point fourty-five.

ollegr [7]4 years ago
6 0

Answer: 45 cents

Step-by-step explanation: Unit price means the cost per unit. In this case, the cost per notepad.

Since we know that it costs $3.15 for 7 notepads, to find the cost for 1 notepad, we need to divide 7 into $3.15 or 7 into 3.15.

I used long division wish I have shown in the image attached and ended up with .45 which means that each notepad costs 45 cents.

So the unit price for 7 notepads is 45 cents.

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What will be the value of median of a moderately asymmetrical distribution? If the mean and mode are 30 and 24 respectively.
sineoko [7]

The mean, the median and the mode are measures of central tendency, and they are related in some many ways, depending on the type of distribution.

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Mode = 3 * Median - 2 * Mean

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Read more at:

brainly.com/question/15669207

7 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
Vlad [161]

Answer

P(A) = 0.30

P(B) = 0.77

P(A\ n\ B) = 0.22

P(A\ u\ B) = 0.85

Explanation:

Given

See attachment for proper data presentation

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

Yes = 22 and No = 8

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

P(A) = 0.30

Solving (b): P(B)

We only consider data in the Yes column.

Here:

(1) = 22    (2) = 25 and (3) = 30

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

P(B) = 0.77

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

P(A\ n\ B) = 0.22

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

P(A\ u\ B) = 0.85

7 0
3 years ago
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