Find the output for the graph y = -6x + 25 when the input value is 3. = y = [?]
1 answer:
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Answer:
The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}
Step-by-step explanation:
- The domain of the function is the values of x which make the
function defined
- The rang is the corresponding values of y with the domain
- The parent function of f(x) is g(x) = IxI
- The graph of this function represented by 2 lines starting from
the origin, one of them with positive slope and the other with negative
slope and both of them over the x-axis
- The Domain of g(x) is {x : x ∈ R} where R is the set of real numbers
- That mean the domain of g(x) is all real numbers
- The range of g(x) is {y : y ≥ 0}
- That mean the range is all real numbers greater than or equal to zero
- f(x) is the image of g(x) after some transformations
- g(x) multiplied by 2 that mean vertical stretch.
- Then x add by 2 that mean horizontal translation to the left by 2 units
- Then subtract 8 from it means vertical translation down by 8 units
- The figure of f(x) is the same lines but stretched vertically away from
x-axis and moved to the left 2 units and down 8 units
- That means the image of the origin is (-2 , -8)
- So the domain does not change it is the all real numbers
- The domain of f(x) is {x : x ∈ R}
- But the range changes is because the graph of the function starts
from -8 not from 0
- Then the range of f(x) is {y : y ≥ -8}
* The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}
- <em>Look to the attached graph for more understand</em>
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t
v(t) can be obtained by integrating a(t)
v(t) =
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)