There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
Answer: 3log5(2) - 1 or ~0,29203
Step-by-step explanation:
2log5(4) - log5(10)
log5(4^2) - log5(10)
log5(4^2/10)
log5(16/10)
log5(8/5)
Log5(8) - log5(5)
log5(2^3) - 1
3log5(2) - 1
Answer:
For the function
y = cos(1/2 x)
The x-intercept can be calculated by equating the function to zero and solving for x. So,
y = cos(1/2 x) = 0
1/2 x = arc cos 0
1/2 x = 90° +180°n
x =2 (90° +180°n)
x = 180° + 360°n
or converting to radians
x = (180° + 360° n)(π/180°)
x = π + 2π n
where n is any whole number
if n = 0
x = π
Therefore, the x-intercept is π or π+2π n
Step-by-step explanation:
Plz give me brainleist worked hard thanks
Answer:
3/4
Step-by-step explanation:
Fraction of names called last week = 1/4 of a page
Fraction called this week = 1/2 of a page
The number of pages worth of people called ;
This is an addition problem, as the total will be the sum. Of the fractions called this week and last week
Hence,
Total page worth of names called :
(1/4 + 1/2) = (1 + 2) / 4 = 3/4
In 4 seconds, number of beats = 28
In 1 sec., it is = 28/4 = 7
Now, In 30 seconds, it would be: 30 * 7 = 210
In short, Your Answer would be: 210 beats
Hope this helps!
