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amid [387]
3 years ago
9

How can i explain that i am useing multiplication to solve the proportion

Mathematics
1 answer:
kow [346]3 years ago
8 0
In order for us to answer this question, more information is needed.
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A ride at a park has room for 8 children to ride at once.
djyliett [7]

Answer:

6

Step-by-step explanation:

45/8=5.625

Since there are .625 children left, we need to add another ride to fill in what's left.

4 0
2 years ago
Properties of multiplication 50b=10<br>what is the answer?
poizon [28]
B is equal to 1/5. Hope I was able to help

8 0
3 years ago
What is the area of a 24-inch rug? Use area of a circle formula: A = πr²
zvonat [6]
That’s 5 inch g , so like u see the 24 inch rug right then u do + 4 inch to get 5 inch fam
7 0
2 years ago
Compare fraction 2/8 and 7/8
umka21 [38]

Answer:

2/8 < 7/8

Step-by-step explanation:

Since the denominators are the same, we compare the numerators

2<7  so

2/8 < 7/8

3 0
3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &2&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &3&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
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