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V125BC [204]
4 years ago
12

Solve for x. 9x=5x 20 enter your answer in the box. x =

Mathematics
2 answers:
const2013 [10]4 years ago
7 0
Collect the like terms
9x-5x=20
4x=20 divide both sided by 4
x=5
Lapatulllka [165]4 years ago
5 0

Yep! just took the test the answer was x=5!

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The length of a rectangle is six times its width.
ololo11 [35]
Alright, so we'll be playing a little with variables around here. The question tells you the length of a rectangle is six times its width, or that l=6w. 

The perimeter of a rectangle is 2l + 2w (two times the length + two times the width). Since we established that l=6w...

2(6w) + 2w = 98 yd
12w + 2w = 98 yd
14w=98 yd
w=7 yd. 

But it doesn't stop there. We found that the width is 7 yd. So the length is 6w, or 6 x 7 yd, which is 42 yd. To find the area of a rectangle, you multiply the length by the width. 

So...42 yd x 7 yd = 294 yd^2. 

Hope that helped. 
8 0
4 years ago
Explain what it means to be a solution when there are two lines on a graph
Wittaler [7]

Answer:

Step-by-step explanation:

When the lines intersect, the point of intersection is the only point that the two graphs have in common. So the coordinates of that point are the solution for the two variables used in the equations.

4 0
3 years ago
How much does the bag of peanuts weigh now?
SVEN [57.7K]

Answer:

1/12

Step-by-step explanation:

subtract the two :)

4 0
3 years ago
Read 2 more answers
Solve absolute value equations and show work step by step ​please due tomorrow
Sergio039 [100]

Answer:

12) x = 10 or x = -10

13) b = 3 or b = -3.

14) r = 6 or r = -2

15)  n = 0 or -2

Step-by-step explanation:

12) Given, 4|x| + 3 = 43

Now, for x ≥ 0, |x| = x and for x < 0, |x| = -x

So, for x ≥ 0, the equation becomes 4x + 3 = 43

⇒ 4x = 40

⇒ x = 10

Again, for x < 0, we have - 4x + 3 = 43

⇒ - 4x = 40

⇒ x = - 10

Therefore, the solution of the equation is x = 10 or x = -10. (Answer)

13) Given, 3|b| + 5 = 14

Now, for b ≥ 0, |b| = b and for b < 0, |b| = -b

So, for b ≥ 0, the equation becomes 3b + 5 = 14

⇒ 3b = 9

⇒ b = 3

Again, for b < 0, we have - 3b + 5 = 14

⇒ - 3b = 9

⇒ b = - 3

Therefore, the solution of the equation is b = 3 or b = -3. (Answer)

14) 9|2r - 4| + 1 = 73

Now, for 2r - 4 ≥0 i.e. r ≥ 2, then

9(2r - 4) + 1 = 73

⇒ 2r - 4 = 8

⇒ 2r = 12

⇒ r = 6

Again, for (2r - 4) < 0 i.e. r < 2, then

9(4 - 2r) + 1 = 73

⇒ 4 - 2r = 8

⇒ 2r = - 4

⇒ r = -2

Hence, the solutions are r = 6 and r = -2  (Answer)

15) For, 10n + 10 ≥ 0 i.e. n ≥ -1, then

1 + 4(10n + 10) = 41

⇒ 10n + 10 =10

⇒ 10n = 0

⇒ n = 0

Again, for 10n + 10 < 0 i.e. n < -1, then

1 - 4(10n + 10) = 41

⇒ 10n + 10 = - 10

⇒ 10n = -20

⇒ n = -2  

Hence, the solution is n = 0 or -2 (Answer)

4 0
4 years ago
Jeanette is writing the first five terms of an arithmetic sequence. She knows that a1 is -27 and the common difference is 5. She
Musya8 [376]
No they are not correct.  She should be adding 5 to the next terms instead of subtracting them.  i.e. -27, -22, -17, -12, ...
6 0
3 years ago
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