Answer:
<em>The probability that it is grape juice, given that the juice is not sugar free is </em><em>0.769 or 76.9%</em>
Step-by-step explanation:

A cooler has 12 apple juices and 15 grape juices. So total 27 juices are there.
Out of 12 apple juices, 9 of the apple juices are sugar free, so 3 are not sugar free.
Out of 15 grape juices, 5 of the grape juices are sugar free, so 10 are not sugar free. So,


Putting the values,

Answer:
1.0 - 0.6 = 0.4 (1.0 and 0.6)
OR
12.6 - 12.2 = 0.4 (12.6 and 12.2)
Let the numbers be a and b and b>a
2a=3b and 3(b-a)=2(b-a)+13
Solving the first for a:
2a=3b
a=3b/2, now using this value of a in the second equation gives you:
3(b-3b/2)=2(b-3b/2)+13 upon performing indicated operations.
3b-9b/2=2b-6b/2+13 making all terms have a common denominator of 2
(6b-9b)/2=(4b-6b+26)/2 multiplying the whole equation by 2
6b-9b=4b-6b+26 combining like terms
-3b=-2b+26 adding 2b to both sides
-b=26 dividing both sides by -1
b=-26, since a=3b/2
a=3(-26)/2
a=-39
So the numbers are -39 and -26
check...
2a=3b becomes:
2(-39)=3(-26)
-78=-78
3(b-a)=2(b-a)+13 becomes:
3(-26--39)=2(-26--39)+13
3(13)=2(13)+13
39=26+13
39=39
correct :P
Y-13. 3/3=1. 1+12=13. you can’t combine unlike terms so the answer is y-13.