G:$2.99
R:$16.99
For every 1R we have 3G.
1R+3G=$16.99+3($2.99)
So 1R+3G=$25.96
If we take $129.80÷$25.96, we get 5.
So let's try 5.
5R+15G=5($16.99)+15($2.99)
So 5R+15G=$129.80
1/5(25-5a)=4-a
⇔5-a=4-a
NO SOLUTION
let f=1
then
1^2+3(1)
=5
2(1)-1(5+1)(3)=19
hope this is the answer plz mark brillent thank you my friend
22:2 33:3 44:4
Hope this helps
K to the 6th power, because you can add k to k to the 5th power to make k to the 6th, and n to the 5th and n to the -5th cancel each other out.