Answer:
F(x) =2(1/2 x2-6x) +C
Step-by-step explanation:
Hope it helps
Answer:
Sum of their present ages = 20 years
Step-by-step explanation:
Present age :
Neha's age = x years
Reemas' age = x - 4
After 5 years:
Neha's age = (x +5) years
Reemas' age = (x - 4 + 5 ) = x + 1
Sum of the ages of Reema and Neha will be 30
Therefore,
x + 5 + x + 1 = 30
x + x + 5 + 1 = 30
2x + 6 = 30
2x = 30 - 6
2x = 24
x = 24/2
x = 12
Neha's age = 12 years
Reema's age = 12 - 4 = 8 years
Sum of their present ages = 12 + 8 = 20 years
Q=4
If not then I guess I’m just not smart
I attached the document with the answers and work with the formulas. Since the formulas and fractions don't work very well with this site (especially the pi symbol, they should fix that).
:)
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docx
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a) 0.88
b) 0.02
c) 0.01
d) 0.99
Step-by-step explanation:
Step one: State the given parameters



Step 2 : Obtain the probability that a unit does not have a type 1 defect
= 
= 
= 0.88
Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?
The probability of the unit having both type 2 and type 3 defect is denoted as 
This is calculated as

= 0.02
Therefore P(D_{2} n D_{3} ) = 0.02
Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect
Let
denote the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.
This can be calculated as follows :

= 0.02 - 0.01
= 0.01
Step 4 : Obtain the probability that a unit has at most two defects
P(at most 2 defects) = 1 - P(all three defects)
= 
= 1 - 0.01
= 0.99