3 years ago

WHICH INQUALITY IS EQUAL TO -1 > M+4

Mathematics

1 answer:

PIT_PIT [208]3 years ago

5 0

Answer:

m<−5

Step-by-step explanation:

Step 1: Flip the equation.

m+4<−1

Step 2: Subtract 4 from both sides.

m+4−4<−1−4

m<−5

Hope this helped <3

You might be interested in

What is the slope of y=-1/3x+4the slope of y=-1/3x+4

charle [14.2K]

Answer:

-1/3

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

8 0

3 years ago

Apply the distributive property to create an equivalent expression. 1/5(15+10k)

lara [203]

3 + 2k

This is because multiplying by 1/5 is like dividing each term by 5

7 0

4 years ago

Read 2 more answers

The circumference of a circle is 100.48 feet. What is the circle's diameter?

sweet-ann [11.9K]

Answer:

631.334460 ft

Step-by-step explanation:

i think

5 0

3 years ago

Read 2 more answers

64,569 rounded to the thousands

Zina [86]

The 4 is in the thousands place and looking to the right of the 4 is a 5. The rule is less than 4 leave it the same; 5 or more add 1 to the number.

So the answer would be 65,000.

3 0

3 years ago

√3=1.732 find the value of√75+1/2√48-√198

Nookie1986 [14]

Answer:

12.124-3 $\sqrt{22}$

Step-by-step explanation:

$\sqrt{75} = \sqrt{5^{2}*3} \\$

$\sqrt{48}= \sqrt{2^{2}*2^{2}*3} \\$

$\sqrt{198} =\sqrt{3^{2}*2*11} \\$

$\sqrt{75} +\frac{1}{2} *\sqrt{48} - \sqrt{198} \\\\\sqrt{5^{2}*3} +\frac{1}{2} *\sqrt{2^{2}*2^{2}*3} - \sqrt{3^{2}*2*11} \\\\5\sqrt{3} +\frac{1}{2} *4 \sqrt{3} - 3 \sqrt{2*11} \\\\5\sqrt{3} +2 \sqrt{3} - 3 \sqrt{22} \\\\5*1.732 +2*1.732 - 3 \sqrt{22} \\\\8.66 + 3.464 - 3 \sqrt{22}\\\\12.124- 3 \sqrt{22}$

4 0

3 years ago