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3 years ago

64,569 rounded to the thousands

1 answer:

3 0

The 4 is in the thousands place and looking to the right of the 4 is a 5. The rule is less than 4 leave it the same; 5 or more add 1 to the number.

So the answer would be 65,000.

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A cylinder has a height of 10 millimeters and a radius of 3 millimeters. What is its volume?

elena-s [515]

Answer:

18312.5mm³

Step-by-step explanation:

Given parameters:

Height of cylinder = 18mm

radius = 18mm

Unknown:

Volume of the cylinder = ?

Solution:

The volume of cylinder is given as;

Volume = π r ² h

Insert the given parameters and solve;

Volume = 3.14 x 18² x 18

Volume = 18312.5mm³

6 0

3 years ago

Read 2 more answers

If 30(x-10)=120 then x=

Crazy boy [7]

30(x - 10) = 120

Use distributive property to remove the parenthesis
30x - 30(10) = 120
30x - 300 = 120

move the constant to the right side
30x - 300 = 120
30x = 120 + 300
30x = 420

solve for x by moving 30 to the right side, multiplication will be division after moved to the right side
30x = 420
x = 420/30
x = 14

The value of x is 14

3 0

3 years ago

What is the y-intercept of the graph of the linear function

hichkok12 [17]

Answer:

there's no graph, so I can't really answer this in a definite form. If you're looking for it in the equation, though, it's the "+b" in "y=mx+b".

Step-by-step explanation:

8 0

3 years ago

Write an equation of cosine function with amplitude 2 and a period 4pi

Arisa [49]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now.. hmmm let's see, keeping in mind the template above

so, amplitude of 2, A=2, thus |A| = ±2, so, you can use either

and period of 4π, well, that simply means that

$\bf \cfrac{2\pi }{B}=4\pi \implies \cfrac{2\pi }{4\pi }=B\implies \cfrac{1}{2}=B\\\\
-----------------------------\\\\

\begin{array}{llll}
f(\theta)=&\pm 2cos&\left(\frac{1}{2}\theta \right)\\
&\ \uparrow &\ \uparrow \\
&A&B
\end{array}$

8 0

4 years ago

What is 6(x+4)+1 what is the answer

docker41 [41]

Answer:

6x-23

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers