Answer:
The inequality describing the situation is:

Step-by-step explanation:
Joe works as a busboy at the rate of = $7 per hour
Let the number of hours he works as a bus boy this month be =
hours
∴ Amount Joe would make this month working as a busboy =
Joe works as a theater usher at the rate of = $9 per hour
Let the number of hours he works as a theater usher this month be =
hours
∴ Amount Joe would make this month working as a theater usher =
Total amount Joe would make this month =
His goal is earn more than $1500 this month.
∴ The situation can be represented in the following inequality:

Answer:
-9/5 , -8/5 , -7/5, -6/5 , -5/5.
Step-by-step explanation:
brainliest plsssss
Answer:
((2 x + 1) (4 x^2 - 2 x + 1))/8
Step-by-step explanation:
Factor the following:
x^3 + 1/8
Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:
(8 x^3)/8 + 1/8
(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:
(8 x^3 + 1)/8
8 x^3 + 1 = (2 x)^3 + 1^3:
((2 x)^3 + 1^3)/8
Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):
((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8
1^2 = 1:
((2 x + 1) ((2 x)^2 - 2 x + 1))/8
Multiply each exponent in 2 x by 2:
((2 x + 1) (2^2 x^2 - 2 x + 1))/8
2^2 = 4:
Answer: ((2 x + 1) (4 x^2 - 2 x + 1))/8
25 candy in a bag, if 2/5 or 40% of candy is caramels. Then 10 in each bag is caramels.
Your answer would be C.
Answer:1. GCF of the group ( 6 x - 3 ) is 3.
2. The common binomial factor is 2 x - 1.
3. The factored expression is: ( 2 x - 1 ) ( 7 x + 3 ).
Step-by-step explanation:
14 x² + 6 x - 7 x - 3 =
= ( 14 x² - 7 x ) + ( 6 x - 3 ) =
= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =
= ( 2 x - 1 ) ( 7 x + 3 )