We have that
H(t)=-4.9t²<span>+50t + 2
we know that
</span><span>The initial height of the rocket, in meters is for t=0 sec
fot t=0
H(t)=</span>-4.9*0²+50*0 + 2------> H(t)=2 m
the answer is
The initial height of the rocket is 2 m
They want you to find the y intercept. This is the point where the curve or line crosses the y axis. To find the y intercept, plug in x = 0
y = 3x+4
y = 3*x + 4
y = 3*0 + 4 ... notice x has been replaced with 0
y = 0 + 4
y = 4
So when x = 0, the value of y is y = 4. This means the y intercept is located at the point (0,4). This is all for problem 1. Problem 2 is handled much the same way.
V = PI x r^2 x H
471 = 3.14 x 5 x H
471 = 15.7 x h
h = 471 / 15.7 = 30 cm
314/ 15.7 = 20 cm
30-20 = 10 cm difference
