Answer:
I have this same question do you have the answer??
Step-by-step explanation:
Simplifying
3x + 1 = 3[x + -1] + 4
Reorder the terms:
1 + 3x = 3[x + -1] + 4
Reorder the terms:
1 + 3x = 3[-1 + x] + 4
1 + 3x = [-1 * 3 + x * 3] + 4
1 + 3x = [-3 + 3x] + 4
Reorder the terms:
1 + 3x = -3 + 4 + 3x
Combine like terms: -3 + 4 = 1
1 + 3x = 1 + 3x
Add '-1' to each side of the equation.
1 + -1 + 3x = 1 + -1 + 3x
Combine like terms: 1 + -1 = 0
0 + 3x = 1 + -1 + 3x
3x = 1 + -1 + 3x
Combine like terms: 1 + -1 = 0
3x = 0 + 3x
3x = 3x
Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x
Combine like terms: 3x + -3x = 0
0 = 3x + -3x
Combine like terms: 3x + -3x = 0
0 = 0
This equation is an identity, all real numbers are solutions.
Answer:
log2(9) = 3
Step-by-step explanation:
Please check logarithm
I hope this helps you
y=-2x
x+3.(-2x)=15
x-6x=15
-5x=15
x=-3
y=-2.-3=6
