Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
2 = |3x|
−4/5x + 1/25 = 0
3x = 4 − x
B does not lie on the graph of the line -2x + 3y = 6
If we substitute the x and y value from B into the equation; ( 6 = x and -2 = y), both sides of the equation will not be equal;
-2x + 3y = 6
-2 (6) + 3(-2) = 6
-12 + (-6) = 6
-18 = 6
Since both sides of the equal sign are not 6, the point does not lie on the line.
Answer:
This is what it should look like:
You would lay out the equation for area
A=(L)(W)
then plug in the variables
8x^2+26x+12=2x+5(L)
then solve for L