Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
Answer: True
Explanation: The importance of mitotic cell division is to produce two daughter cells that are genetically identical. The genetic materials of the parent cell are arranged and moved towards the two spindle poles with the help of the spindles so that there will be an even distribution of the parent cell's genetic materials between the resulting two daughter cells.
Rotary, oscillating, linear, reciprocating
There is two answers to that because there are two different forms of cells that being animal and plant cells. The cell is surrounded by a cell or plasma membrane. Unlike the animal cell the plant cell also has a cell wall surrounding it. This is made of cellulose and is very rigid.