Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
The statement that describes the volumes of the two figures relate is: <em>The </em><em>volume of the cone</em><em> is 1/3 of the </em><em>volume of the cylinder</em>
Given the following:
Volume of cylindrical-shaped container = 12 cubic feet
Volume of cone-shaped container = 4 cubic feet
Ratio of the volume of the cone to the volume of the cylinder = 4 : 12 = 1 : 3
Therefore the statement that describes the volumes of the two figures relate is: <em>The </em><em>volume of the cone</em><em> is 1/3 of the </em><em>volume of the cylinder</em>
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brainly.com/question/13677400
the answer is A. hope this helps
