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ch4aika [34]
4 years ago
7

A trapezoid with bases that measure 8 inches and 11 inches has a height of 3 inches. What is the area of the trapezoid?

Mathematics
1 answer:
gavmur [86]4 years ago
3 0
Area= 1/2(height)×(base↓1+base↓2)
Area=1/2(3)×(8+11)
Area=1/2(3)×(19)
Area=1/2(57)
Area=57/2 OR 28.5
Thus, the area of the trapezium is 28.5inches^2
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Answer:

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Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

<u>Area of square 1: 81 square inches</u>

s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9

<u>Perimeter of square 2: 48 inches</u>

4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15

Hence,

The length of side of largest square is 15 inches

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Answer:  1) 0.10

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The total frequency is 20+120+40+20 = 200.  This means they ran the experiment 200 times.  The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

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