You would use the formatting section of alignment.
Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
The OC level is primarily used as a regional ISP backbone, and occasionally by very large hospitals, universities, or other major enterprises is <u>OC-48.</u>
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<h3>What is the greatest amount of throughput provided by an OC 12?</h3>
OC-12 is a network line with communication speeds of up to 622.08 Mbit/s (payload: 601.344 Mbit/s; overhead: 20.736 Mbit/s). OC-12 lines are generally used by ISPs as wide area network (WAN) connections.
<h3>When using frame relay What is the appellation of the identifier?</h3>
A data-link connection identifier (DLCI) determines the Frame Relay PVC. Frames are routed through one or more virtual circuits determined by DLCIs.
Each DLCI has a permanently configured switching path to a particular destination
To learn more about OC level , refer
brainly.com/question/25899244
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Yes in my opinion. People will say no but there is no right answer
