def print_feet_inch_short(num_feet, num_inches):
#function named print_feet_inch_short takes in two arguments.
print(str(num_feet)+"'",str(num_inches)+"\"")
#output the feet and inch value supplied with the shorthand sign of feet and inch using string concatenation.
num_feet = int(input())
#allows user to specify a feet value and stores it in num_feet
num_inches = int(input())
#allows user to specify an inch value and stores it in num_inch
print_feet_inch_short(num_feet, num_inches)
#calling the function with the number of feets and inches given by user.
Learn more : brainly.com/question/18318709
Answer:
The complete program is as follows:
m_str = input('Input m: ')
mass = float(m_str)
e = mass * 300000000**2
print("e = ",e)
Explanation:
This is an unchanged part of the program
m_str = input('Input m: ')
This converts m_str to float
mass = float(m_str)
This calculates the energy, e
e = mass * 300000000**2
This is an unchanged part of the program
print("e = ",e)
Answer:
The best answer would be
Explanation:
To access this command ...
Select the Format tab - Properties - Paragraph properties - Bleeds and spaces
An example of new technology that is having a negative impact on sustainability is using multiple servers to maintain a cryptocurrency operation.
<h3>How does technology influence sustainability?</h3>
The use of technology is one that have a lot of power to increase productivity, efficiency and cost savings, and others but it is also known to have a negative effect on the environment.
Sustainability implies that one meets the needs of people without having to compromise the power of future posterity to meet their own needs.
Learn more about sustainability from
brainly.com/question/25350238
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
