Question

Which ordered pair makes both inequalities true? Y < –x + 1 and y > x On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, 0). Everything below and to the left of the line is shaded. The second dashed line has a positive slope and goes through (negative 1, negative 1) and (1, 1). Everything above and to the left of the line is shaded. (–3, 5) (–2, 2) (–1, –3) (0, –1) Mark this and return

Answer 1

Answer:

(-2, 2) satisfy both the inequalities.

Step-by-step explanation:

Given:

The line inequalities are:

$yx$

Let us plot the two line inequalities.

In order to plot it on a graph, we must consider two points on it. So, we replace the inequality sign by 'equal to' sign and consider two random points on it.

$y=-x+1$

When $x=0,y=1\ and\ x=1, y=0$

Now, draw a line passing through (0,1) and (1,0). As the inequality says y less than -x + 1, so the region will be below and left of the line with a broken line as shown in the graph with blue shaded region.

Similarly, the other inequality line will pass through (-1, -1) and (1, 1) and the shaded region will be above the broken line as shown in the graph by red region.

Now, the region that is common to both is the solution region. A point in the solution region will satisfy both the inequalities.

As shown on the graph, the point (-2, 2) lie in the solution region and is thus the answer. The remaining choices outside the solution region as shown.

So, the correct choice is (-2, 2).