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likoan [24]
3 years ago
14

Evaluate (x + y ) 0 for x = –3 and y = 5.

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0
(x+y)0
(-3+5)0
(-15)0
THE ANSWER IS 0 BECAUSE YOU ARE MULTIPLYING BY 0
Zielflug [23.3K]3 years ago
6 0

Answer:

<h2>Anything raised to 0 is 1. So this is no different.</h2>

The Answer is <u>1</u>

Step-by-step explanation:

  1. (x+y)∧0
  2. (-3+5)∧0
<h2>2∧0=1</h2><h3>Hope this Helps ('U')</h3><h3>BTW I'm assuming you meant raised to the power of 0 instead of multiplied by 0.</h3>

if not i apologize. 0,0

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Write equations for the vertical and horizontal lines passing through the point , −1−8 .
icang [17]
Vertical line (when y = 0)
⇒ Equation : x = -1

Horizontal line (when x = 0)
⇒ Equation : y = -8

--------------------------------------------------------------
Answer: x = -1, y = -8
--------------------------------------------------------------
7 0
4 years ago
Find integra of xlnxdx
Mademuasel [1]

Answer:

\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

\displaystyle \int x \ln x \:\: \text{d}x

To integrate the given integral, use Integration by Parts:

\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}

\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}

\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2

Therefore:

\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}

Learn more about integration here:

brainly.com/question/27805589

brainly.com/question/27983581

brainly.com/question/27759474

5 0
2 years ago
6 divided by 2/3 = tell me thee answer in fraction form
Maksim231197 [3]

Answer:

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8 0
3 years ago
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Elena-2011 [213]

Answer:

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Step-by-step explanation:

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3 years ago
a container holds 15 pennies 8 nickels and 10 dimes you will randomly select two coins without replacement what is the probabili
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<span>A container holds 15 pennies, 8 nickels, and 10 dimes. 
You will randomly select two coins without replacement. 
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