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Anton [14]
3 years ago
12

You have different video games. How many different ways can you arrange the games side by side on a​ shelf? You can arrange the

different video games in nothing different ways.
Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

See Explanation below

Step-by-step explanation:

<em>This question has missing details because the number of video games is not stated;</em>

<em>However, you'll arrive at your answer if you follow the steps I'll highlight;</em>

<em></em>

The question requests for the number of arrangement; That means we're dealing with permutation

Let's assume the number of video games is n;

To arrange n games, we make use of the following permutation formula;

^nP_n = \frac{n!}{(n-n)!}

Simplify the denominator

^nP_n = \frac{n!}{0!}

0! = 1; So, we have

^nP_n = \frac{n!}{1}

^nP_n = n!

Now, let's assume there are 3 video games;

This means that n = 3

^3P_3 = 3!

^3P_3 = 3 * 2 * 1

^3P_3 = 6\ ways

<em>So, whatever the number of video games is; all you have to do is; substitute this value for n;</em>

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Step-by-step explanation:

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3 years ago
What is the solution for -10 &lt; x - 9?
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-10 < x - 9

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The correct answer would be option C

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Sidana [21]
Y -:5 = 2/3x + 6 because 6 is 2/3 of 9
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Answer:

<em>~ 0.375 centimeters of the snowflake in real life ~</em>

Step-by-step explanation:

Let us plan out our steps, and solve for each:

<em>1. Given the information, let us create a proportionality as such:</em>

      48       =           1      ⇒   x - centimeters of the snowflake in real life

       18                    x

<em>2. Now let us cross multiply, and solve through simple algebra for x:</em>

48 * x = 18,

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Answer:

Parallel

Step-by-step explanation:

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