Factor: y = x^7 + 65x^4 + 64x

(HELP ASAP PLEASE!!)

olasank [31]

Answer:

Shirts = $7

Shorts $17

Step-by-step explanation:

Let:

T - shirts

S - shorts

We can make two equations out of this problem:

4T + 3S = $79

7T + 8S = $185

Through substitution we can solve for one of the unknowns. We make one equation to solve for an unknown

$4T+3S=\$79\\\\3S = \$79-4T\\\\S=\dfrac{\$79-4T}{3}$

We use the formula of S and insert it into the other equation:

$7T+8(\dfrac{\$79-4T}{3}) = \$185\\\\7T + \dfrac{\$632-32T}{3}=\$185\\\\\dfrac{\$632-32T}{3}=\$185-7T\\\\\$632-32T=3(\$185-7T)\\\\$632-32T=\$555 - 21T\\\\-32T+21T=\$555-\$632\\\\-11T=-\$77\\\\\dfrac{-11T}{11}=\dfrac{-\$77}{11}\\\\T = \$7$

Thus T-shirts are $7 each.

Now that we know T, we can use it to solve for the other unknown. You can use it on any of the formulas.

$4T+3S=\$79\\\\4(\$7) + 3S = \$79\\\\\$28+3S =\$79\\\\3S=\$79-\$28\\\\3S=\$51\\\\S=\dfrac{\$51}{3}\\\\S = \$17$

We know then that Shorts are $17 each.

7 0

2 years ago

Find the value of x. What kind of angles are these?

VLD [36.1K]

Answer:

$\displaystyle Corresponding\:Angles; 40 = x$

Step-by-step explanation:

Corresponding Angles are <em>congruent</em>, therefore you set both angle measures equal to each other:

$\displaystyle 135° = [3x + 15]° → 120 = 3x; 40 = x$

I am joyous to assist you at any time.

5 0

2 years ago

Read 2 more answers

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then