<span>MgO + HCl = MgCl2* + H2*O
To balance an equation, you have to have both the reactants and products side equal.
Mg = 1 Mg = 1
H = 1 H = 2
Cl = 1 Cl = 2
MgO + 2HCl = MgCl2 + H2*O
We added the coefficient 2, so they could balance. </span>
D. It is the heat required to change a gram of substance from a liquid to a gas.
Explanation:
The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.
- It is also known as the enthalpy of vaporization.
- The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
- This heat of vaporization is dependent on the pressure conditions the process is taking place.
- Different liquids have their heat of vaporization.
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Answer:
Explanation:
Let's break it down:
- Butane- A 4 carbon alkane
- Methyl - A CH₃ group
- 2,2 - Both the Methyl groups are attached at carbon 2
We can now draw the structure of 2,2-dimethyl butane using the following steps:
- Draw the backbone (butane)
- Draw the substituents (2 methyl groups at carbon 2)
1. An ionic bond is an attraction between oppositely charged ions. A covalent bond is sharing of electrons between atoms.
2. A bond between two atoms
3. covalent bond
4. They have different properties because the arrangement of atoms is different.
5. Mutual attraction between the nuclei and electrons in two different atoms
The volume of the nitrous oxide gas is 1729.3 Liters
<h3>What is the number of moles of gas present in 3.40 kg of nitrous oxide?</h3>
The number of moles of gas present in 3.40 kg of nitrous oxide is determined from the formula below:
Numbers of moles = mass/molar mass
the mass of nitrous oxide = 3.40 kg or 3400 g
the molar mass of nitrous oxide = 44.013 g/mol
Moles of gas = 3400 / 44.013
Moles of gas = 77.25 moles
Using the ideal gas equation to determine the volume of the gas:
PV= nRT
V = nRT/P
where;
- V is the volume of gas
- n is the number of moles of gas
- R is molar Gas constant = 0.082 L.atm/mol/K
- T is the temperature of the gas
V = 77.25 * 0.082 * 273 / 1
The volume of the gas = 1729.3 Liters
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