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andrey2020 [161]

3 years ago

12

Manny’s sister bought school supplies that totaled $457. After a coupon, the total came down to $418. Which equation shows how t

o find a, the amount of money spent on supplies after the coupon?

1 answer:

kompoz [17]3 years ago

4 0

Answer:

if you are subtracting then you would : 457-418=39

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Which set(s) represents a function?

jek_recluse [69]

Answer:

1, 2, 3

Step-by-step explanation:

If the y's (right numbers have more than one number its not a function) hope this helps! :)

4 0

2 years ago

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A tire at the top of a hill starts rolling down the hill. If the diameter of the tire is 36 inches, how many inches has the tire

vredina [299]

The answer would be 360pi.

5 0

3 years ago

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Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

3 years ago

High grade steel consists of 85% iron and 15% magnese. Low grade steel consists of 67% iron and 33% mag ese. NASA orders 500 ton

Mamont248 [21]

Answer:

$361\dfrac{1}{9}$ tons of high steel and $138\dfrac{8}{9}$ tons of low steel

Step-by-step explanation:

Let x be the number of tons of high grade steel and y be the number of tons ow low grade steel needed.

In x tons of high grade steel there are

$0.85x$ tons of iron

$0.15x$ tons of magnese

In y tons of low grade steel there are

$0.67y$ tons of iron

$0.33y$ tons of magnese

NASA orders 500 tons of steel, so

$x+y=500$

and specifies that it must be in the proportion 80% iron and 20% magnese, so

$0.85x+0.67y=500\cdot 0.8\\ \\0.85x+0.67y=400$

From the first equation,

$x=500-y$

Substitute it into the second equation:

$0.85(500-y)+0.67y=400\\ \\425-0.85y+0.67y=400\\ \\-0.18y=-25\\ \\y=\dfrac{2,500}{18}=138\dfrac{8}{9}\ tons\\ \\x=361\dfrac{1}{9}\ tons$

7 0

4 years ago

Michelle has a jar of quarters and dimes totalling to 3.10 if there are sixteen coins in the jar how many more quarters are ther

Sav [38]

Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10

0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes

q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters

so there are (10 - 6) = 4 more quarters then dimes

5 0

3 years ago