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Alenkasestr [34]
4 years ago
11

What is the answer to (((4^2-(7 x 2))4x2)-2x3+(5x2)÷2-5?

Mathematics
1 answer:
LiRa [457]4 years ago
6 0

{4}^{2}  = 4 \times 4 = 16
((16 - (14)) = 2
((2)4 \times 2) = (2 \times 8) = 16
((16) - 2 \times 3) = 16 - 6 = 10
(10 + (5 \times 2)) = 10 + (10) = 20
(20 \div 2) = 10
10 - 5 = 5
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The ancient Greeks could bisect an angle using only a compass and straightedge.A. TrueB. False
Gala2k [10]

Answer: True.

The ancient Greeks could bisect an angle using only a compass and straightedge.

Step-by-step explanation:

The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.

The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.

Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.

This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.

As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .

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4 years ago
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Thandi deposits 850 into a bank. the bank will pay a simple interest rate of 8% per year. how much money will Thandi get when sh
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2 years ago
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

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3 years ago
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MrRa [10]

Answer:

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3 years ago
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