What is the answer to (((4^2-(7 x 2))4x2)-2x3+(5x2)÷2-5?

1 answer:

6 0

${4}^{2} = 4 \times 4 = 16$
$((16 - (14)) = 2$
$((2)4 \times 2) = (2 \times 8) = 16$
$((16) - 2 \times 3) = 16 - 6 = 10$
$(10 + (5 \times 2)) = 10 + (10) = 20$
$(20 \div 2) = 10$
$10 - 5 = 5$

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The area of the shaded segment is 100cm^2. Calculate the value of r.

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Hello,

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$cos(40)= \frac{h}{r} \\ \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)$

Now we can find its area:
$A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)$

The subtraction of the two areas is 100cm^2, then:

$A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm$

Answer: r= 1.59cm

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3 years ago

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The probability that a single radar set will detect an enemy plane is 0.9. if we have five radar sets, what is the probability t

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The probability that a single radar set will detect an enemy plane is 0.9. if we have five radar sets, what is the probability that exactly four sets will detect the plane?

Solution: The given random experiment follows binomial distribution with $p=0.9,n=5$