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KATRIN_1 [288]
3 years ago
15

Which faces have an area of 28in squared

Mathematics
2 answers:
madreJ [45]3 years ago
7 0
The lowest rectangle is 28in because you just multiply the 4 and the 7
kvasek [131]3 years ago
3 0
The very last square the one with 4in
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The answer is c........
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Which equation is the standard form equation of the line that passes through the point (-2, 0) and has a slope of 4?
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4x-y=-8
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3 years ago
Represent the situation using an equation. Check your answer with a visual model or numeric method.
Lyrx [107]

Answer:

Step-by-step explanation:

n(30/100)=27

n=100(27)/30

n=90

3 0
3 years ago
A garbage container is to be constructed out of 400 ft2 of material. The vessel will have a square base and an open top. Find th
sveticcg [70]

Answer:

  11.547 ft wide by 5.774 ft high

  769.800 ft³ capacity

Step-by-step explanation:

Volume is maximized for a given area by having the area of a pair of opposite sides equal the area of the bottom. That means the overall area of the container is 3 times the area of the bottom. Then the square bottom will have a width of ...

  w = √(400/3) ≈ 11.547 . . . feet

The height is half that, so is ...

  h = w/2 = 11.547/2 ≈ 5.774 . . . feet

The capacity is then ...

  w²h = (11.547 ft)²(5.774 ft) = 769.800 ft³

The container is 11.547 ft wide by 5.774 ft high. It has a capacity of 769.800 cubic feet.

_____

You want to maximize w^2h subject to w^2 + 4wh = 400. Solving the constraint equation for h, we get h = (400 -w^2)/(4w) and the volume we want to maximize can be written as ...

  V = w(400-w^2)/4

This will be an extreme when dV/dw = 0, so we want to solve ...

  dV/dw = 0 = 100 -(3/4)w^2

  w^2 = 400/3

  w = √(400/3) . . . . . as above

7 0
3 years ago
Shelby mixes a 25% bleach solution with 5 cups of a 10% bleach solution, resulting in a 20% bleach solution. The table shows the
german

Answer:

10

Step-by-step explanation:

We will use a system of equations to solve this.  We do not know how much of the 25% bleach solution is used; we will use x to represent this.  We know that 5 cups of the 10% solution was used.  We do not know how much of the resulting solution we have; we will use y to represent this.  This gives us the equation

x+5 = y

Using the decimal forms of the percentages for each solution, we have 0.25x (25% solution for x cups), 0.1(5) (10% solution for 5 cups) and 0.2y (20% solution for y cups); this gives us the equation

0.25x+0.1(5) = 0.2y

This gives us the system

\left \{ {{x+5=y} \atop {0.25x+0.1(5)=0.2y}} \right.

To use elimination, we will make the coefficients of x the same by multiplying the top equation by 0.25:

\left \{ {{0.25(x+5=y)} \atop {0.25x+0.5=0.2y}} \right. \\\\\left \{ {{0.25x+1.25=0.25y} \atop {0.25x+0.5=0.2y}} \right.

We will now subtract the second equation from the first:

\left \{ {{0.25x+1.25=0.25y} \atop {-(0.25x+0.5=0.2y)}} \right. \\\\0.75 = 0.05y

Divide both sides by 0.05:

0.75/0.05 = 0.05y/0.05

15 = y

There were 15 cups of the resulting 20% solution.  Substituting this into the first equation, we have

x+5=15

Subtract 5 from each side:

x+5-5=15-5

x = 10

7 0
3 years ago
Read 2 more answers
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