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Feliz [49]
3 years ago
11

The random variable X has the following probability mass function.X -1 0 2 6 7P(x) 0.3 0.1 0.3 0.2 0.1Answer the next 4 question

s.5. Find the probability P( -1 < X ≤ 2) = ______6. Find the cumulative distribution function F(x) and calculate F(3.2) = _____________7. E(X) = ___________8. Var(X) = __________
Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that X has the following pdf.

x -1 0 2 6 7 Total

P(X) 0.3 0.1 0.3 0.2 0.1 1

xP(X) -0.3 0 0.6 1.2 0.7 2.2

x^2P(X) 0.3 0 1.2 7.2 4.9 13.6

     

Var(x) 13.6-2.2^2  8.76    

Std dev   2.959729717    

5) P( -1 < X ≤ 2) = P(0)+P(2)\\= 0.1+0.3=0.4

6. Find the cumulative distribution function F(x) and calculate F(3.2) =

x -1 0 2 6 7

P(X) 0.3 0.1 0.3 0.2 0.1

F(x) 0.3 0.4 0.7 0.9 1

F(3.2) = P(X<3.2) = ___F(X<6) = 0.7__________

7. E(X) = ______2.2_____

8. Var(X) = ____8.76______

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Answer:

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Step-by-step explanation:

Given : PQRS is a trapezoid on a coordinate plane P(7,4) Q(10,4) R(13,-1) S(8,-1).

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PS=\sqrt{(-1-4)^{2}+(8-7)^2 }

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