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Sphinxa [80]
2 years ago
6

A pyramid is placed inside a prism as shown. The pyramid has the same base area, B, as the prism but half the height, h, of the

prism. Which expression gives the volume of the pyramid?
V = 2/3bh
V = 1/4bh
V = 2bh
V = 1/6bh
Mathematics
1 answer:
Alona [7]2 years ago
4 0
The general formula of a pyramid with any base is 1/3 bh where b is the area of the base and h is the height. In this case, the height of the pyramid is said to be twice the height of the prism, h. Hence the area becomes 1/3 b*2h or equal to option A. 2/3 bh
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vivado [14]

Answer:

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Step-by-step explanation:

For 3 pink flowers=2 white flowers

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Now

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72 pink flowers=48 white flowers

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3 years ago
What's the equation for the line that passes through the given point and is parallel to the graph of the given line (3,-1);y=2x-
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3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
2 years ago
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Yuki888 [10]

Answer:

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Step-by-step explanation:

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while if its rectangular ( all side are not equal ) shaped

      V = Length * Width * Height (thickness)

      V = L * W * 3 = 3LW inch^{3}

5 0
2 years ago
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