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Afina-wow [57]
3 years ago
10

Rewrite the equation in Ax+By=C form.Use integers for A, B, and C.y-1=-5(x-5)​

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

5x + y = 26

Step-by-step explanation:

Step 1: Distribute

y - 1 = -5x + 25

Step 2: Add 1 to both sides

y = -5x + 26

Step 3: Move 5 to the other side

5x + y = 26

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Give an example of a Cubic Bionomial Polynomial.
DerKrebs [107]
<span>g = 9.8 m/s2 and PE = m × g × h.

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3 0
3 years ago
Belle bought 18 seeds in order to plant an herb garden for her grandma. Of the seeds she bought, 10 were parsley seeds.
Harrizon [31]

Answer:

  0.3431

Step-by-step explanation:

Here, it can work well to consider the seeds from the group of 18 that are NOT selected to be part of the group of 15 that are planted.

There are 18C3 = 816 ways to choose 3 seeds from 18 NOT to plant.

We are interested in the number of ways exactly one of the 10 parsley seeds can be chosen NOT to plant. For each of the 10C1 = 10 ways we can ignore exactly 1 parsley seed, there are also 8C2 = 28 ways to ignore two non-parsley seeds from the 8 that are non-parsley seeds.

That is, there are 10×28 = 280 ways to choose to ignore 1 parsley seed and 2 non-parsley seeds.

So, the probability of interest is 280/816 ≈ 0.3431.

___

The notation nCk is used to represent the expression n!/(k!(n-k)!), the number of ways k objects can be chosen from a group of n. It can be pronounced "n choose k".

6 0
3 years ago
Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given E(-2,3), F(1,6)

|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given F(1,6), G(4,3)

|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0
3 years ago
Read 2 more answers
Can you please provide me step by step instructions on how to work this problem?
IgorC [24]
Whats the problem if u forgot type it over and type the problem
8 0
3 years ago
While mining, John found a large metal bar that contained 15 pounds of zinc. John also determined that the bar was 60% zinc. Wha
finlep [7]

Answer:

The total weight of the metal bar in pounds is 25 pounds

Step-by-step explanation:

Now, we have a metal bar which has a content of 60% zinc corresponding to 15 pounds.

Mathematically, let’s say the total weight of the metal composite is x pounds. It is 60% of this that is 15 pounds which is the content of the zinc

Mathematically;

60/100 * x = 15

60x = 15 * 100

60x = 1500

x = 1500/60

x = 25 pounds

4 0
3 years ago
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