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miss Akunina [59]
3 years ago
15

Taylor wants to paint his rectangular deck that is 42 ft long and 28 ft wide. A gallon of pain covers 350 sq ft. How many gallon

s of pain will Taylor need to cover the entire deck? Write and solve an equation to find the area of the deck.
Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0
42ft*28ft=1176ft²
1176ft
²/350ft²=3.36
So, you multiply 42 and 28 in order to find out how large of a space you are needing to paint. You then find out your deck is 1176 square feet. You would then divide by the paint bucket's coverage to find out how many buckets you would need. Then all you have to do is round up so you completely cover it and your answer is 4 buckets of paint, assuming a bucket of paint contains a gallon of paint..
xeze [42]3 years ago
4 0
He will need 3 111/116 gallons of paint. Equation: (42x28)÷350=3 111/116 gallons of paint
Area Equation: 42x28=1176 square feet
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Suppose △ITH≅△APG.<br><br> Which congruency statement is true?
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When the two triangles are congruent, then the corresponding angles and sides are congruent to each other.

By being congruent, the corresponding angles which are congruent are:

IT \cong AP, TH \cong PG, IH \cong AG

Therefore, IH \cong AG

SO, Option 2 is the correct answer.

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A 99 ft length of wire is to be cut into 2 pieces, so that the longer piece is eight feet longer than six times the shorter piec
Serhud [2]

here's the solution,

let the length of shorter peice = x

then the lenght of longer peice = 6x + 8

now, we know that the sum of length of peices measures 99 feet,

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PLEASE HELP: The mass of a ball is 128 g. It has a density of 0.5 g/cm³. What is the volume of the ball? Show your work and plac
tiny-mole [99]

Answer:

Part 1) The volume of the ball is 256 cm³

Part 2) The radius of the ball is 3.94 cm

Step-by-step explanation:

Part 1) we know that

The density is equal to divide the mass by the volume

D=m/V

Solve for the volume

The volume is equal to divide the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

Part 2) what is the radius of the ball?

we know that

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we have

V=256\ cm^{3}

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