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kirza4 [7]
3 years ago
8

A diver descends to a location of −5014 meters relative to the surface of the water. He then descends another 1012 meters.

Mathematics
2 answers:
Nataly_w [17]3 years ago
5 0
Its -60 3/4


Hope this helps!~
Arlecino [84]3 years ago
5 0

Answer: Using operations with fractions, the diver's final location is:

- 60 3/4 meters relative to the surface of the water (60 3/4 meters below the surface of the water).


Solution:

Initial location: -50 1/4 meters

He descends another 10 1/2 meters: -10 1/2 meters

Final location = Initial location - 10 1/2 meters

Final location = - 50 1/4 meters - 10 1/2 meters

Final location = - (50+10) (1/4+1/2) meters

Final location = - 60 [(1)(1)+2(1)]/4 meters

Final location = - 60 (1+2)/4 meters

Final location = - 60 3/4 meters

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son4ous [18]

one angle is 3x-3

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T is the midpoint of SU. Find ST, TU and SU. <br><br><br> 10x-14 5x+16<br><br>S———T———U
jeka94

since T is the midpoint of SU, then ST = TU.

\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}

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