The correct answer is entropy.
In fact, second law of thermodynamics states that the total entropy of an isolated system can never decrease. It can remain constant if the system is in equilibrium or in case of a reversible process: however, perfectly reversible process do not exist in the real world, so the entropy of a system always increases whenever there is a process that involves energy changes.
The pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.
Explanation:
Pressure acting on any surface is the amount of force experienced by that surface in a given area. So it is the ratio of force to area of the object under consideration.
As here the force is said to be 50 N and the area is said to be 20 m², the pressure will be
So, pressure is inversely proportional to the area and directly proportional to the force acting on the surface. As it can be seen that on decreasing the area to 0.5 m², there will be increase in the pressure as shown below,
Thus, the pressure increased to 100 Nm² from 2.5 Nm² on decreasing the area from 20 m² to 0.5 m².
Similarly, if 10 Pa pressure is acting on an area of 3 m², then the force acting on this region will be the product of pressure with the area.
Thus, the pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.
I believe the answer is C
On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.
Answer:
F = 4856.32 N
Explanation:
Given,
A satellite is orbiting earth at a distance from Earth surface, h = 35000 m
The mass of the satellite, m = 500 Kg
The radius of the Earth, R = 6.371 x 10⁶ m
The mass of the Earth, M = 5.972 x 10²⁴ Kg
The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²
The force between the Earth and the satellite is given by the formula
F = GMm/(R+h)² N
Substituting the values in the above equation
F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²
= 4856.32 N
Hence, the force between the planet and the satellite is, F = 4856.32 N