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2 years ago

What is this reflection

1 answer:

4 0

Reflection is basically a 'flip' of a shape over the line of reflection. Very often, reflections are performed using coordinate notation.

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*PLEASE HELP* *ANY IRRELEVANT ANSWERS WILL BE REPORTED AS SPAM*

drek231 [11]

Answer:

67.307

Step-by-step explanation:

30×25=750

100×80=8000

750+8000=8750

8750/130=67.307... total hits divided by total games

8 0

1 year ago

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How do you calculate the volume of a cone when given the height and diameter? Describe the steps used to solve.

fiasKO [112]

First find the radius by taking half the diameter. Use the radius to find the base area by using the formula for the area of a circle. Find the product of the base area and height, and then take one-third of the product.

7 0

3 years ago

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Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

2 years ago

Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3

poizon [28]

The midpoint formula for a segment is:

$x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}$

apply to points R and P

$\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}$

using the definition of slope find the slope of the segment

$m=\frac{y_2-y_1}{x_2-x_1}$

apply to points R and P

$\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}$

to lines are parallel when the slopes are the same

$\mleft\Vert m=1\mright?$

two lines are perpendicular when the product of the slopes is equal to -1

$\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}$

7 0

1 year ago

Please help 20 points!!

frutty [35]

Where is the question?

7 0

2 years ago

Read 2 more answers