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adell [148]
4 years ago
10

Solve this logic number sequence puzzle by the correct digit

Mathematics
1 answer:
otez555 [7]4 years ago
3 0
8080=6 because there are 6 "0s" or circle shaped objects that make up the number. For example, 8=2 (there are two circles.)


<u>Using the same logic,</u>
1357=0 because there are no circles.
2022=1; there is 1 circle.
1999=3; three circles.
6666=4; there are four circles.
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Order from least to greatest -4 7, 0, 4,12 -1 -2
svet-max [94.6K]

-4, -2, -1, 0, 4, 7, 12

Hope this helps~ ^^

7 0
3 years ago
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Find the unit rate for 4:1 and 2:2/3
Nuetrik [128]

Answer:

2

Step-by-step explanation:

4 miles

÷ 2

2 hours

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2 miles

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4 0
3 years ago
Solve for x in the picture please.
SCORPION-xisa [38]

Answer:

X=20

Step-by-step explanation:

The 3 angles all add up to 180º because they are a straight line.

3x + 80 + 2x = 180

5x + 80 = 180

5x + (80-80) = 180-80

5x = 100

5x/5 = 100/5

X=20

Hope this helps!

8 0
3 years ago
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A test has 20 true/false questions. What is the probability that a student passes the test if they guess the answers? Passing me
Minchanka [31]

Using the binomial distribution, it is found that:

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

For each question, there are only two possible outcomes, either the guess is correct, or it is not. The guess on a question is independent of any other question, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 20 questions, hence n = 20.
  • Each question has 2 options, one of which is correct, hence p = \frac{1}{2} = 0.5

The probability is:

P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148

P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046

P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011

P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002

P(X = 16) = C_{20,19}.(0.5)^{19}.(0.5)^{1} = 0

P(X = 17) = C_{20,20}.(0.5)^{20}.(0.5)^{0} = 0

Then:

P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0207

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

You can learn more about the binomial distribution at brainly.com/question/24863377

6 0
3 years ago
Need this asap! questions in the ss
svetlana [45]

Answer/Step-by-step explanation:

Part A:

Evidence 1: the line passes through the point of origin, (0, 0)

Evidence 2: it has a unit rate or constant of proportionality, k = y/x = 5/3

Part B:

When extended, if the ray passes through the point, (18, 30), then y/x of this point, should give us the same unit rate (k) of 5/3 of the graph.

Thus:

y/x = 30/18

Simplify

= 5/3

Thus, it has the same unit rate of the graph, therefore, the ray passes through the point (18, 30).

7 0
3 years ago
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